If radius of earth were to shrink by 1% its mass remaining same, acceleration due to gravity on eart

English

Gujarati

Hindi

7.Gravitation

normal

If the radius of the earth were to shrink by $1\%$ its mass remaining the same, the acceleration due to gravity on the earth's surface would

A

Decrease by $2\%$

B

Remain unchanged

C

Increase by $2\%$

D

Becomes zero

Solution

$\because \quad \mathrm{g}=\frac{\mathrm{GM}}{\mathrm{R}^{2}}$

$\frac{\Delta g}{g}=-2 \frac{\Delta R}{R}=-2(-1)=2 \%$ increases by

Standard 11

Physics

Share

Similar Questions

At what height above the earth's surface is the value of $'g'$ is same as in a $200\, km$ deep mine …….. $km$

normal

The variation of acceleration due to gravity $g$ with distance $d$ from centre of the earth is best represented by ($R =$ Earth's radius)

normal

The mass of planet is $\frac{1}{9}$ of the mass of the earth and its radius is half that of the earth. If a body weight $9\,N$ on the earth. Its weight on the planet would be …….. $N$

normal

Figure shows the variation of the gravitatioal acceleration $a_g$ of four planets with the radial distance $r$ from the centre of the planet for $r\geq $ radius of the planet. Plots $1$ and $2$ coincide for $r\geq R_2$ and plots $3$ and $4$ coincide for $r \geq R_4$. The sequence of the planets in the descending order of their densities is

normal

The angular speed of earth in $rad/s$, so that bodies on equator may appear weightless is : [Use $g = 10\, m/s^2$ and the radius of earth $= 6.4 \times 10^3\, km$]

normal