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1.Set Theory
easy
જો ગણ $A$ અને $B$ માટે$A = \{ (x,\,y):y = {e^x},\,x \in R\} $; $B = \{ (x,\,y):y = x,\,x \in R\} ,$ હોય તો . .
A
$B \subseteq A$
B
$A \subseteq B$
C
$A \cap B = \phi $
D
$A \cup B = A$
Solution
(c) Since, $y = {e^x}$ and $y = x$ do not meet for any $x \in R$
$\therefore A \cap B = \phi $.
Standard 11
Mathematics
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