If the straight line $ax + by = 2;a,b \ne 0$ touches the circle ${x^2} + {y^2} - 2x = 3$ and is normal to the circle ${x^2} + {y^2} - 4y = 6$, then the values of a and b are respectively

  • A

    $1, -1$

  • B

    $1, 2$

  • C

    $ - \frac{4}{3},1$

  • D

    $2, 1$

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