If the sum of two unit vectors is also a unit | vedclass

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Question

(b)

$|\vec{R}|=|\vec{A}+\vec{B}|=\sqrt{A^2+B^2+2 A B \cos 	heta}$

$|\vec{A}|=|\vec{B}|=|\vec{R}|=1$

$1=1+1+2 	imes 1 	imes 1 	imes \cos \

Vedclass · Accepted Answer

$\sqrt{3}, 120^{\circ}$

Vedclass · Answer

(b)

$|\vec{R}|=|\vec{A}+\vec{B}|=\sqrt{A^2+B^2+2 A B \cos 	heta}$

$|\vec{A}|=|\vec{B}|=|\vec{R}|=1$

$1=1+1+2 	imes 1 	imes 1 	imes \cos 	heta$

$\cos 	heta=-\frac{1}{2} \Rightarrow 	heta=120^{\circ}$

$|\vec{R}|=|\vec{A}-\vec{B}|=\sqrt{A^2+B^2-2 A B \cos 120^{\circ}}$

$=\sqrt{1^2+1^2-2 	imes 1 	imes 1 	imes\left(-\frac{1}{2}ight)}=\sqrt{3}=|\vec{A}-\vec{B}|$

If the sum of two unit vectors is also a unit vector. then magnitude of their difference and angle between the two given unit vectors is ..............

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