If system of equations, a^2 x - ay = 1 - a & bx + (3 - 2b) y = 3 + a possess a unique solution x

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3 and 4 .Determinants and Matrices

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If the system of equations, $a^2 x - ay = 1 - a$ & $bx + (3 - 2b) y = 3 + a$ possess a unique solution $x = 1, y = 1$ then :

A

$a = 1 ; b = - 1$

B

$a = - 1 , b = 1$

C

$a = 0 , b = 0$

D

none

Solution

put $x = 1\, $ and $ \,y = 1$ and solve for $a\, $ and $\, b$ . In $B\, $ and $\, C$ system has infinite solutions

Standard 12

Mathematics

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