If the system of equations

$ x+(\sqrt{2} \sin \alpha) y+(\sqrt{2} \cos \alpha) z=0 $

$ x+(\cos \alpha) y+(\sin \alpha) z=0 $

$ x+(\sin \alpha) y-(\cos \alpha) z=0$

has a non-trivial solution, then $\alpha \in\left(0, \frac{\pi}{2}\right)$ is equal to :

  • [JEE MAIN 2024]
  • A

     $\frac{3 \pi}{4}$

  • B

     $\frac{7 \pi}{24}$

  • C

     $\frac{5 \pi}{24}$

  • D

     $\frac{11 \pi}{24}$

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  • [JEE MAIN 2024]

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