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3 and 4 .Determinants and Matrices
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જો રેખાઓની સંહતિ $x+ ay+z\,= 3$ ; $x + 2y+ 2z\, = 6$ ; $x+5y+ 3z\, = b$ ને એકપણ ઉકેલ શકય ન હોય તો . . .
A
$a\, = 1$ , $b\,\ne 9$
B
$a\,\ne - 1$ , $b\, = 9$
C
$a\, = - 1$ , $b = 9$
D
$a\, = -1$ , $b\,\ne 9$
(JEE MAIN-2018)
Solution
As the system of equation has no solution then $\Delta $ should be zero and at lest one of ${\Delta _1},{\Delta _2}$ and ${\Delta _3}$ should not be zero.
$\therefore \Delta = \begin{array}{*{20}{c}}
1&a&1\\
1&2&2\\
1&5&3
\end{array} = 0$
$ \Rightarrow – a – 1 = 0 \Rightarrow a = – 1$
${\Delta _2} = \begin{array}{*{20}{c}}
1&3&1\\
1&6&2\\
1&b&3
\end{array} \ne 0$
$ \Rightarrow b \ne 9$
Standard 12
Mathematics
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