3 and 4 .Determinants and Matrices
hard

જો રેખાઓની સંહતિ $x+ ay+z\,= 3$ ; $x + 2y+ 2z\, = 6$ ; $x+5y+ 3z\, = b$ ને એકપણ ઉકેલ શકય ન હોય તો  . . .

A

$a\, = 1$ , $b\,\ne 9$

B

$a\,\ne - 1$ , $b\, = 9$

C

$a\, = - 1$ , $b = 9$

D

$a\, = -1$ , $b\,\ne 9$

(JEE MAIN-2018)

Solution

As the system of equation has no solution then $\Delta $ should be zero and at lest one of ${\Delta _1},{\Delta _2}$ and ${\Delta _3}$ should not be zero.

$\therefore \Delta  = \begin{array}{*{20}{c}}
1&a&1\\
1&2&2\\
1&5&3
\end{array} = 0$

$ \Rightarrow  – a – 1 = 0 \Rightarrow a =  – 1$

${\Delta _2} = \begin{array}{*{20}{c}}
1&3&1\\
1&6&2\\
1&b&3
\end{array} \ne 0$

$ \Rightarrow b \ne 9$

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.