If the truth value of the Boolean expression $((\mathrm{p} \vee \mathrm{q}) \wedge(\mathrm{q} \rightarrow \mathrm{r}) \wedge(\sim \mathrm{r})) \rightarrow(\mathrm{p} \wedge \mathrm{q}) \quad$ is false then the truth values of the statements $\mathrm{p}, \mathrm{q}, \mathrm{r}$ respectively can be:
$\mathrm{T}\, \mathrm{F} \,\mathrm{T}$
$\mathrm{F\,F\,T}$
$\mathrm{T\,F\,F}$
$\mathrm{F\,T\,F}$
Consider the statement : "For an integer $n$, if $n ^{3}-1$ is even, then $n$ is odd." The contrapositive statement of this statement is
The negation of the expression $q \vee((\sim q) \wedge p)$ is equivalent to
Which of the following is not a statement
Negation of “Paris in France and London is in England” is
Negation of the statement $(p \vee r) \Rightarrow(q \vee r)$ is :