If three geometric means be inserted between | vedclass

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Question

(c) $2,\,{g_1},\;{g_2},\;{g_3},\;32$ where

$a = 2,\;ar = {g_1},\;a{r^2} = {g_2},\;a{r^3} = {g_3}$ and $a{r^4} = 32$

Now $2 	imes {r^4} = 32$

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(c) $2,\,{g_1},\;{g_2},\;{g_3},\;32$ where

$a = 2,\;ar = {g_1},\;a{r^2} = {g_2},\;a{r^3} = {g_3}$ and $a{r^4} = 32$

Now $2 	imes {r^4} = 32$

$\Rightarrow {r^4} = 16 = {(2)^4} $

$\Rightarrow r = 2$.

Then third geometric mean $ = a{r^3} = 2 	imes {2^3} = 16$.

Aliter : By formula, ${G_3} = 2.{\left( {\frac{{32}}{2}} ight)^{3/4}} = 2\;.\;8 = 16$.

If three geometric means be inserted between $2$ and $32$, then the third geometric mean will be

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