Gujarati
Hindi
7.Gravitation
hard

If three particles each of mass $M$ are placed at the corners of an equilateral triangle of side $a$ , the potential energy of the system and the work done if the side of the triangle is changed from $a$ to $2a$ , are

A

$\frac{{3GM}}{a},\frac{{3GM}}{{2a}}$

B

$- \frac{{3GM^2}}{a},\frac{{3GM^2}}{{2a}}$

C

$- \frac{{3GM^2}}{a},\frac{{3GM^2}}{{4a}}$

D

$- \frac{{3GM^2}}{a},\frac{{3GM}}{{2a}}$

Solution

Potential energy $=-\frac{3 \mathrm{GM}(\mathrm{M})}{\mathrm{a}}$

Work done $=$ change in $\mathrm{PE}$

$=-\frac{3 \mathrm{GM}^{2}}{2 \mathrm{a}}-\left(-\frac{3 \mathrm{GM}^{2}}{\mathrm{a}}\right)$

$=\frac{3 \mathrm{GM}^{2}}{2 \mathrm{a}}$

Standard 11
Physics

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