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7.Gravitation
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In order to shift a body of mass $m$ from a circular orbit of radius $3R$ to a higher radius $5R$ around the earth, the work done is
A
$\frac{{3GMm}}{{5R}}$
B
$\frac{1}{{15}}\frac{{GMm}}{R}$
C
$\frac{{GMm}}{{2R}}$
D
$\frac{{GMm}}{{5R}}$
Solution
$W = \Delta ME = – \frac{{GMm}}{{2\left( {5R} \right)}} – \left( { – \frac{{GMm}}{{2\left( {3R} \right)}}} \right) = \frac{1}{{15}}\frac{{GMm}}{R}$
Standard 11
Physics
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