If two vectors vec{A} and vec{B} having equal | vedclass

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Question

The   magnitude   of   resultant   vector

$R^{\prime}=\sqrt{a^2+b^2+2 a b \cos 	heta}$

Here $a=b=R$

Vedclass · Accepted Answer

$|\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}}|=2 \mathrm{R} \cos \left(\frac{	heta}{2}ight)$

Vedclass · Answer

The   magnitude   of   resultant   vector

$R^{\prime}=\sqrt{a^2+b^2+2 a b \cos 	heta}$

Here $a=b=R$

Then $R^{\prime}=\sqrt{R^2+R^2+2 R^2 \cos 	heta}$

$=R \sqrt{2} \sqrt{1+\cos 	heta}$

$=\sqrt{2} R \sqrt{2 \cos ^2 \frac{	heta}{2}}$

$=2 R \cos \frac{	heta}{2}$

If two vectors $\vec{A}$ and $\vec{B}$ having equal magnitude $\mathrm{R}$ are inclined at an angle $\theta$, then

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