In a $G.P.,$ the $3^{rd}$ term is $24$ and the $6^{\text {th }}$ term is $192 .$ Find the $10^{\text {th }}$ term.
Here, $a_{3}=a r^{2}=24$ ........$(1)$
and $a_{6}=a r^{5}=192$ ...........$(2)$
Dividing $(2)$ by $(1),$ we get $r=2 .$ Substituting $r=2$ in $(1),$ we get $a=6$
Hence $\quad a_{10}=6(2)^{9}=3072$
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