8. Sequences and Series
easy

In a $G.P.,$ the $3^{rd}$ term is $24$ and the $6^{\text {th }}$ term is $192 .$ Find the $10^{\text {th }}$ term.

A

$3072$

B

$3072$

C

$3072$

D

$3072$

Solution

Here, $a_{3}=a r^{2}=24$      ……..$(1)$

and   $a_{6}=a r^{5}=192$          ………..$(2)$

Dividing $(2)$ by $(1),$ we get $r=2 .$ Substituting $r=2$ in $(1),$ we get $a=6$

Hence $\quad a_{10}=6(2)^{9}=3072$

Standard 11
Mathematics

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