In a $G.P.,$ the $3^{rd}$ term is $24$ and the $6^{\text {th }}$ term is $192 .$ Find the $10^{\text {th }}$ term.

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Here, $a_{3}=a r^{2}=24$      ........$(1)$

and   $a_{6}=a r^{5}=192$          ...........$(2)$

Dividing $(2)$ by $(1),$ we get $r=2 .$ Substituting $r=2$ in $(1),$ we get $a=6$

Hence $\quad a_{10}=6(2)^{9}=3072$

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