Two condensers of capacities 2C and C are joined in parallel and charged upto potential V . battery

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2. Electric Potential and Capacitance

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Two condensers of capacities $2C$ and $C$ are joined in parallel and charged upto potential $V$. The battery is removed and the condenser of capacity $C$ is filled completely with a medium of dielectric constant $K$. The $p.d.$ across the capacitors will now be

$\frac{{3V}}{{K + 2}}$

$\frac{{3V}}{K}$

$\frac{V}{{K + 2}}$

$\frac{V}{K}$

(IIT-1988)

Solution

(a) ${q_1} = 2CV,$ ${q_2} = CV$
Now condenser of capacity $C$ is filled with dielectric $K$, therefore $C_2 = KC$
As charge is conserved
${q_1} + {q_2} = (C'_2+ 2C)V'$ $==>$ $V' = \frac{{3CV}}{{(K + 2)C}} = \frac{{3V}}{{K + 2}}$

Standard 12

Physics

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hard

(JEE MAIN-2017)

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medium

Two condensers of capacities $2C$ and $C$ are joined in parallel and charged upto potential $V$. The battery is removed and the condenser of capacity $C$ is filled completely with a medium of dielectric constant $K$. The $p.d.$ across the capacitors will now be

Solution

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