In a dark room of photography, generally red light is used. The reason is
In a dark room of photography, generally red light is used. The reason is
- A
Most of the photographic films are not sensitive to red light
- B
The frequency for red light is low and hence the energy $hv$ of photons is less
- C
$(a)$ and $(b)$ both
- D
None of the above
Similar Questions
When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectrons and their maximum kinetic energy are $N$ and $K$ respectively. If the intensity of radiation is $2I$, the number of emitted electrons and their maximum kinetic energy are respectively
When monochromatic radiation of intensity $I$ falls on a metal surface, the number of photoelectrons and their maximum kinetic energy are $N$ and $K$ respectively. If the intensity of radiation is $2I$, the number of emitted electrons and their maximum kinetic energy are respectively
- [AIPMT 2010]
In photoelectric effect if the intensity of light is doubled then maximum kinetic energy of photoelectrons will become
In photoelectric effect if the intensity of light is doubled then maximum kinetic energy of photoelectrons will become
In photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon
In photoelectric effect, the K.E. of electrons emitted from the metal surface depends upon
When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is $6.0 V$. This potential drops to $0.6 V$ if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively? $\left[\right.$ Take $\left.=\frac{h c}{c}=1.24 \times 10^{-6} Jm ^{-1}.\right]$
When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is $6.0 V$. This potential drops to $0.6 V$ if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively? $\left[\right.$ Take $\left.=\frac{h c}{c}=1.24 \times 10^{-6} Jm ^{-1}.\right]$
- [IIT 2022]
In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
In photo electric effect
$A.$ The photocurrent is proportional to the intensity of the incident radiation.
$B.$ Maximum Kinetic energy with which photoelectrons are emitted depends on the intensity of incident light.
$C.$ Max. $K.E$ with which photoelectrons are emitted depends on the frequency of incident light.
$D.$ The emission of photoelectrons require a minimum threshold intensity of incident radiation.
$E.$ Max. K.E of the photoelectrons is independent of the frequency of the incident light.
Choose the correct answer from the options given below:
- [JEE MAIN 2023]