In a group of $65$ people, $40$ like cricket, $10$ like both cricket and tennis. How many like tennis only and not cricket? How many like tennis?

Vedclass pdf generator app on play store
Vedclass iOS app on app store

Let $C$ denote the set of people who like cricket, and $T$ denote the set of people who like tennis

$\therefore n(C \cup T)=65, n(C)=40, n(C \cap T)=10$

We know that:

$n(C \cup T)=n(C)+n(T)-n(C \cap T)$

$\therefore 65=40+n(T)-10$

$\Rightarrow 65=30+n(T)$

$\Rightarrow n(T)=65-30=35$

Therefore, $35$ people like tennis.

Now,

$(T-C) \cup(T \cap C)=T$

Also.

$(T-C) \cap(T \cap C)=\varnothing$

$\therefore n(T)=n(T-C)+n(T \cap C)$

$\Rightarrow 35=n(T-C)+10 $

$\Rightarrow n(T-C)=35-10=25$

Thus, $25$ people like only tennis.

Similar Questions

In a certain school, $74 \%$ students like cricket, $76 \%$ students like football and $82 \%$ like tennis. Then, all the three sports are liked by at least $......\%$

  • [KVPY 2009]

Out of $800$ boys in a school, $224$ played cricket, $240$ played hockey and $336$ played basketball. Of the total, $64$ played both basketball and hockey; $80$ played cricket and basketball and $40$ played cricket and hockey; $24$ played all the three games. The number of boys who did not play any game is

In a class of $140$ students numbered $1$ to $140$, all even numbered students opted Mathematics course, those whose number is divisible by $3$ opted Physics course and those whose number is divisible by $5$ opted Chemistry course. Then the number of students who did not opt for any of the three courses is

  • [JEE MAIN 2019]

In a city $20$ percent of the population travels by car, $50$ percent travels by bus and $10$ percent travels by both car and bus. Then persons travelling by car or bus is......$\%$ 

In a group of students, $100$ students know Hindi, $50$ know English and $25$ know both. Each of the students knows either Hindi or English. How many students are there in the group?