- Home
- Standard 12
- Physics
11.Dual Nature of Radiation and matter
easy
In a Millikan's oil drop experiment the charge on an oil drop is calculated to be $6.35 \times {10^{ - 19}}C$. The number of excess electrons on the drop is
A
$3.9$
B
$4$
C
$4.2$
D
$6$
Solution
(b) $n = \frac{Q}{e} = \frac{{6.35 \times {{10}^{ – 19}}}}{{1.6 \times {{10}^{ – 19}}}} \approx 4$
Standard 12
Physics
