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11.Dual Nature of Radiation and matter
easy
In the Millikan's experiment, the distance between two horizontal plates is $2.5 \,\,cm$ and the potential difference applied is $250\,\, V$ . The electric field between the plates will be ....... $V/m$
A
$900 $
B
$10000$
C
$625$
D
$6250$
Solution
(b) Electric field $ = \frac{V}{d} = \frac{{250}}{{2.5 \times {{10}^{ – 2}}}} = 10000\;V/m$.
Standard 12
Physics
