In a parallel plate condenser, radius of each circular plate is 12,cm and distance between plates is

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2. Electric Potential and Capacitance

medium

In a parallel plate condenser, the radius of each circular plate is $12\,cm$ and the distance between the plates is $5\,mm$. There is a glass slab of $3\,mm$ thick and of radius $12\,cm$ with dielectric constant $6$ between its plates. The capacity of the condenser will be

$144 \times {10^{ - 9}}\,F$

$40\,pF$

$160\,pF$

$1.44\,\mu F$

Solution

(c) $C = \frac{{{\varepsilon _0}A}}{{d – t + \frac{t}{K}}} = \frac{1}{{4\pi \times 9 \times {{10}^9}}}.\frac{{\pi \,{{(0.12)}^2}}}{{\left( {2 + \frac{1}{2}} \right)\,{{10}^{ – 3}}}}$
$ = \frac{{2 \times 144 \times {{10}^{ – 10}}}}{{36 \times 5}} = 160\,pF$

Standard 12

Physics

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Solution

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