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8.Electromagnetic waves
easy
In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10}\,Hz$ and amplitude $48\,Vm ^{-1}$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $=3 \times 10^8\,m s ^{-1}$)
A
$1.6 \times 10^{-6}\,T$
B
$1.6 \times 10^{-9}\,T$
C
$1.6 \times 10^{-8}\,T$
D
$1.6 \times 10^{-7}\,T$
(NEET-2023)
Solution
$C =\frac{ E _0}{ B _0}$
$B _0=\frac{ E _0}{ C }$
$=\frac{48}{3 \times 10^8}$
$=1.6 \times 10^{-7}\,T$
Standard 12
Physics
