14.Probability
hard

एक पाँसे को उछालने पर सम उछालों में $1$ आने की प्रायिकता है

A

$\frac{5}{{36}}$

B

$\frac{5}{{11}}$

C

$\frac{6}{{11}}$

D

$\frac{1}{6}$

(IIT-2005)

Solution

(b) अभीष्ट प्रायिकता

$=\left( {\frac{5}{6}} \right)\;\left( {\frac{1}{6}} \right)\; + \;{\left( {\frac{5}{6}} \right)^3}\left( {\frac{1}{6}} \right) + \;{\left( {\frac{5}{6}} \right)^5}\left( {\frac{1}{6}} \right) + …$

$= \frac{{\frac{5}{6}.\frac{1}{6}}}{{1 – {{\left( {\frac{5}{6}} \right)}^2}}} $

$= \frac{5}{{36 – 25}} = \frac{5}{{11}}$.

Standard 11
Mathematics

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