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11.Thermodynamics
medium
In an adiabatic process where in pressure is increased by $\frac{2}{3}\% $ if $\frac{{{C_p}}}{{{C_v}}} = \frac{3}{2},$ then the volume decreases by about
A
$\frac{4}{9}\% $
B
$\frac{2}{3}\% $
C
$4\%$
D
$\frac{9}{4}\% $
Solution
$\frac{\Delta \mathrm{P}}{\mathrm{P}}=-\gamma \frac{\Delta \mathrm{V}}{\mathrm{V}} \quad \frac{2}{3} \times \frac{1}{\gamma}=\frac{\Delta \mathrm{V}}{\mathrm{V}} \quad \frac{\Delta \mathrm{V}}{\mathrm{V}}=-\frac{4}{9} \%$
Standard 11
Physics