In finding the electric field using Gauss Law the formula $|\overrightarrow{\mathrm{E}}|=\frac{q_{\mathrm{enc}}}{\varepsilon_{0}|\mathrm{A}|}$ is applicable. In the formula $\varepsilon_{0}$ is permittivity of free space, $A$ is the area of Gaussian surface and $q_{enc}$ is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
In finding the electric field using Gauss Law the formula $|\overrightarrow{\mathrm{E}}|=\frac{q_{\mathrm{enc}}}{\varepsilon_{0}|\mathrm{A}|}$ is applicable. In the formula $\varepsilon_{0}$ is permittivity of free space, $A$ is the area of Gaussian surface and $q_{enc}$ is charge enclosed by the Gaussian surface. The equation can be used in which of the following situation?
- [JEE MAIN 2020]
- A
Only when the Gaussian surface is an equipotential surface
- B
Only when $|\overrightarrow{\mathrm{E}}|=$ constant on the surface.
- C
For any choice of Gaussian surface.
- D
Only when the Gaussian surface is an equipotential surface and $|\overrightarrow{\mathrm{E}}|$ is constant on the surface.
Similar Questions
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Take $\left.\varepsilon_0=9 \times 10^{-12} C ^2 / Nm ^2\right)$
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Take $\left.\varepsilon_0=9 \times 10^{-12} C ^2 / Nm ^2\right)$
- [JEE MAIN 2023]
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$(b)$ What is the flux through the side of the cylinder?
$(c)$ What is the net outward flux through the cylinder?
$(d)$ What is the net charge inside the cyllnder?
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A hollow cylinder has a charge $q$ coulomb within it. If $\phi$ is the electric flux in units of $volt-meter$ associated with the curved surface $B,$ the flux linked with the plane surface $A$ in units of $V-m$ will be
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- [AIPMT 2007]