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1. Electric Charges and Fields
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Two small spheres each of mass $10 \,mg$ are suspended from a point by threads $0.5 \,m$ long. They are equally charged and repel each other to a distance of $0.20 \,m$. The charge on each of the sphere is $\frac{ a }{21} \times 10^{-8} \, C$. The value of $a$ will be ...... .
$\left[\right.$ Given $\left.g=10 \,ms ^{-2}\right]$
A
$10$
B
$16$
C
$24$
D
$20$
(JEE MAIN-2021)
Solution

$T \cos \theta= mg =10 \times 10^{-6} \times 10=10^{-4}$
$T \sin \theta=\frac{9 \times 10^{9} \times q ^{2}}{0.04}= F$
$\tan \theta==\frac{0.1}{\sqrt{0.24}}=\frac{ F }{ mg }$
$q =\frac{2 \sqrt{10}}{3 \sqrt{\sqrt{24}}} \times 10^{-8}$
$0.95 \times 10^{-8}=\frac{ a }{21} \times 10^{-3}$
$a =20$
Standard 12
Physics
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