1. Electric Charges and Fields
easy

If two charges of $1$ coulomb each are placed $1 \,km$ apart, then the force between them will be ........... $N$

A

$9 \times 10^3$

B

$9 \times 10^{-3}$

C

$9 \times 10^{-4}$

D

$10^{-6}$

Solution

(a)

$F=\frac{9 \times 10^9(1)(1)}{(1000)^2}=9 \times 10^3 \,N$

Standard 12
Physics

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