In how many ways 5 speakers S₁,S₂,S₃,S₄ and S₅ can give speeches one after other if S₃ w

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Gujarati

Hindi

6.Permutation and Combination

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In how many ways $5$ speakers $S_1,S_2,S_3,S_4$ and $S_5$ can give speeches one after the other if $S_3$ wants to speak after $S_1$ & $S_2$

A

$40$

B

$60$

C

$80$

D

$100$

Solution

${S_3}$ speaks after ${S_1}$ and ${S_2}$

${\,^5}{C_3} \times \mathop {2!}\limits_{{S_1}\,\& \,{S_2}} \times \mathop {2!}\limits_{{S_4}\,\& \,{S_5}} = 40$

Standard 11

Mathematics

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