In how many ways a team of 11 players can be formed out of 25 players, if 6 out of them are always t

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In how many ways a team of $11$ players can be formed out of $25$ players, if $6$ out of them are always to be included and $5$ are always to be excluded

$2020$

$2002$

$2008$

$8002$

Solution

(b) Since $5$ are always to be excluded and $6$ always to be included, therefore $5$ players to be chosen from $14$. Hence required number of ways are $^{14}{C_5} = 2002$.

Standard 11

Mathematics

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Solution

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