Gujarati
6.Permutation and Combination
medium

All possible two factors products are formed from numbers $1, 2, 3, 4, ...., 200$. The number of factors out of the total obtained which are multiples of $5$ is

A

$5040$

B

$7180$

C

$8150$

D

None of these

Solution

(b) The total number of two factor products ${ = ^{200}}{C_2}$.

The number of numbers from $1$ to $200$ which are not multiples of $5$ is $160$.

Therefore total number of two factor products which are not multiple of $5$ is $^{160}{C_2}$.

Hence the required number of factors ${ = ^{200}}{C_2}{ – ^{160}}{C_2} = 7180$.

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.