In order to double frequency of fundamental note emitted by a stretched string, length is reduced to

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14.Waves and Sound

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In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$$^{th}$ of the original length and the tension is changed. The factor by which the tension is to be changed, is

$0.37$

$0.67$

$0.89$

$2.25$

Solution

(d) $n = \frac{1}{{2l}}\sqrt {\frac{T}{m}} \Rightarrow n \propto \frac{{\sqrt T }}{l}$
==> $\frac{{{T_2}}}{{{T_1}}} = {\left( {\frac{{{n_2}}}{{{n_1}}}} \right)^2}{\left( {\frac{{{l_2}}}{{{l_1}}}} \right)^2} = {(2)^2}{\left( {\frac{3}{4}} \right)^2} = \frac{9}{4}$

Standard 11

Physics

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(AIPMT-2014)

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In order to double the frequency of the fundamental note emitted by a stretched string, the length is reduced to $\frac{3}{4}$$^{th}$ of the original length and the tension is changed. The factor by which the tension is to be changed, is

Solution

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