In the ellipse, minor axis is 8 and eccentric | vedclass

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(b) Given, minor axis of ellipse $e = 1/\sqrt 2 $ or $b = 4$ and eccentricity $(e) = \sqrt 5 /3$.

We know that in an ellipse, ${e^2} = 1 - \frac{{{

Vedclass · Accepted Answer

$12$

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(b) Given, minor axis of ellipse $e = 1/\sqrt 2 $ or $b = 4$ and eccentricity $(e) = \sqrt 5 /3$.

We know that in an ellipse, ${e^2} = 1 - \frac{{{b^2}}}{{{a^2}}}$ or $\frac{5}{9} = 1 - \frac{{16}}{{{a^2}}}$

or $\frac{{16}}{{{a^2}}} = 1 - \frac{5}{9}$ or ${a^2} = \frac{{16 	imes 9}}{4}$$ = 36$ or $a = 6.$

We also know that major axis of the ellipse $ = 2a = 2 	imes 6 = 12.$

In the ellipse, minor axis is $8$ and eccentricity is $\frac{{\sqrt 5 }}{3}$. Then major axis is

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