Gujarati
Hindi
10-2. Parabola, Ellipse, Hyperbola
normal

If $F_1$ and $F_2$ be the feet of the perpendicular from the foci $S_1$ and $S_2$ of an ellipse $\frac{{{x^2}}}{5} + \frac{{{y^2}}}{3} = 1$ on the tangent at any point $P$ on the ellipse, then $(S_1 F_1) (S_2 F_2)$ is equal to

A

$2$

B

$3$

C

$4$

D

$5$

Solution

We know that the product of perpendiculars from two foci of an ellipse upon any tangent is equal to the square of the semi-minor axis.

$\left(S_{1} F_{1}\right)\left(S_{2} F_{2}\right)=3$

Standard 11
Mathematics

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