In the given figure, a body of mass $M$ is held between two massless springs, on a smooth inclined plane. The free ends of the springs are attached to firm supports. If each spring has spring constant $k,$ the frequency of oscillation of given body is :
$\frac{1}{2 \pi} \sqrt{\frac{ k }{2 M }}$
$\frac{1}{2 \pi} \sqrt{\frac{2 k }{ Mg \sin \alpha}}$
$\frac{1}{2 \pi} \sqrt{\frac{2 k }{ M }}$
$\frac{1}{2 \pi} \sqrt{\frac{ k }{ Mg \sin \alpha}}$
Block $A$ is hanging from a vertical spring and it is at rest. Block $'B'$ strikes the block $'A'$ with velocity $v$ and stick to it. Then the velocity $v$ for which the spring just attains natural length is:
The frequency of oscillation of a mass $m$ suspended by a spring is $'v'$. If mass is cut to one fourth then what will be the frequency of oscillation ?
A $2\, Kg$ block moving with $10\, m/s$ strikes a spring of constant $\pi ^2 N/m$ attached to $2\, Kg$ block at rest kept on a smooth floor. The time for which rear moving block remain in contact with spring will be ... $\sec$
A block of mass $m$ hangs from three springs having same spring constant $k$. If the mass is slightly displaced downwards, the time period of oscillation will be
If the period of oscillation of mass $m$ suspended from a spring is $2\, sec$, then the period of mass $4m$ will be .... $\sec$