1.Relation and Function
easy

In the set $A = \{1, 2, 3, 4, 5\}$, a relation $R$ is defined by $R = \{(x, y)| x, y$ $ \in  A$ and $x < y\}$. Then $R$ is

A

Reflexive

B

Symmetric

C

Transitive

D

None of these

Solution

(c) Since $x\not < x,$ therefore $R$ is not reflexive. Also $x < y$ does not imply that $y < x,$ So $R$ is not symmetric.

Let $x{\rm{ }}R\,y$ and $y\,R\,z$. Then, $x < y$ and $y < z$

==> $x < z$ i.e., $x\,R\,z$. Hence $R$ is transitive.

Standard 12
Mathematics

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