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1.Relation and Function
easy
ગણ $A = \{1,2,3,4, 5\}$ અને સંબંધ $R =\{(x, y)| x, y$ $ \in A$ અને $x < y\}$ તો $R$ એ . . .
A
સ્વવાચક
B
સંમિત
C
પરંપરિત
D
એકપણ નહીં.
Solution
(c) Since $x\not < x,$ therefore $R$ is not reflexive. Also $x < y$ does not imply that $y < x,$ So $R$ is not symmetric.
Let $x{\rm{ }}R\,y$ and $y\,R\,z$. Then, $x < y$ and $y < z$
==> $x < z$ i.e., $x\,R\,z$. Hence $R$ is transitive.
Standard 12
Mathematics