It is estimated that per minute each cm^2 of | vedclass

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Question

Solar constant $=2 \mathrm{cal} / \mathrm{cm}^{2}-\mathrm{min}$
$2 \mathrm{cal} / \mathrm{cm}^{2}-\mathrm{min}=\mathrm{X} \mathrm{J} / \mathrm{m}^{2}

Vedclass · Accepted Answer

$1393.33$

Vedclass · Answer

Solar constant $=2 \mathrm{cal} / \mathrm{cm}^{2}-\mathrm{min}$
$2 \mathrm{cal} / \mathrm{cm}^{2}-\mathrm{min}=\mathrm{X} \mathrm{J} / \mathrm{m}^{2}-\mathrm{sec}$
$X=2$
$\left(\frac{c a l}{J}\right)\left(\frac{\sec }{\min }\right)\left(\frac{m^{2}}{c m^{2}}\right)$
$=2(4.18)\left(\frac{1}{60}\right)(10000)=1393.33$

It is estimated that per minute each $cm^2$ of earth receives about $2\ cal (1\ cal = 4.18\ J)$ of heat energy from the sun. This is called Solar constant. In $SI$ units the value is :-

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