1.Relation and Function
normal

વિધેય $f(x)$=$\sqrt {(x + 4)(1 - x)}  - {\log _2}x$ ના વિસ્તારગણ મા ન્યુનતમ પુર્ણાક .... છે.

A

$-2$

B

$-1$

C

$0$

D

$1$

Solution

$f(x)=\sqrt{(x+4)(1-x)}+\log _{1 / 2} x$

$\because$ $'f'$ is decreasing

minimum value is $f(1)=0.$

Standard 12
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.