Least integer in the range of $f(x)$=$\sqrt {(x + 4)(1 - x)} - {\log _2}x$ is
$-2$
$-1$
$0$
$1$
$f(x)=\sqrt{(x+4)(1-x)}+\log _{1 / 2} x$
$\because$ $'f'$ is decreasing
minimum value is $f(1)=0.$
Let $A = \{ {x_1},\,{x_2},\,…………,{x_7}\} $ and $B = \{ {y_1},\,{y_2},\,{y_3}\} $ be two sets containing seven and three distinct elements respectively. Then the total number of functions $f : A \to B$ that are onto, if there exist exactly three elements $x$ in $A$ such that $f(x)\, = y_2$, is equal to
The number of bijective functions $f :\{1,3,5, 7, \ldots \ldots . .99\} \rightarrow\{2,4,6,8, \ldots \ldots, 100\}$, such that $f(3) \geq f(9) \geq f(15) \geq f(21) \geq \ldots \ldots f(99), \quad$ is
If ${e^x} = y + \sqrt {1 + {y^2}} $, then $y =$
The range of values of the function $f\left( x \right) = \frac{1}{{2 – 3\sin x}}$ is
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