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1.Relation and Function
normal
વિધેય $f(x) = \frac{{\sqrt {1 - {x^2}} }}{{1 + \left| x \right|}}$ નો વિસ્તાર ......... છે.
A
$\left[ {0,1} \right]$
B
$\left[ {0,\frac{1}{{\sqrt 2 }}} \right]$
C
$\left[ {0,\frac{1}{2}} \right]$
D
$\left[ {0,\frac{{\sqrt 3 }}{2}} \right]$
Solution
Put $x = sin \theta $ $y = \frac{{\left| {\sin \theta } \right|}}{{1 + \left| {\cos \theta } \right|}}$
Standard 12
Mathematics