Let $A = \left[ {\begin{array}{*{20}{c}}
  2&b&1 \\ 
  b&{{b^2} + 1}&b \\ 
  1&b&2 
\end{array}} \right]$  where $b > 0$. Then the minimum value of $\frac{{\det \left( A \right)}}{b}$ is

  • [JEE MAIN 2019]
  • A

    $2\sqrt 3$

  • B

    $-2\sqrt 3$

  • C

    $-\sqrt 3$

  • D

    $\sqrt 3$

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