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8. Sequences and Series
hard
જો ${a_1},{a_2}...,{a_{10}}$ એ સમગુણોત્તર શ્રેણીના પદો હોય અને $\frac{{{a_3}}}{{{a_1}}} = 25$ થાય તો $\frac {{{a_9}}}{{{a_{ 5}}}}$ ની કિમત મેળવો.
A
$5^4$
B
$4(5^2)$
C
$5^3$
D
$2(5^2)$
(JEE MAIN-2019)
Solution
$\frac{{{a_3}}}{{{a_1}}} = \frac{{{a_1}{r^2}}}{{{a_1}}} = {r^2}$
$ \Rightarrow {r^2} = 25$
Now $\frac{{{a_9}}}{{{a_5}}} = \frac{{{a_1}{r^8}}}{{{a_1}{r^4}}} = {r^4} = {\left( {25} \right)^2} = {5^4}$
Standard 11
Mathematics
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