8. Sequences and Series
hard

જો ${a_1},{a_2}...,{a_{10}}$ એ સમગુણોત્તર શ્રેણીના પદો હોય અને $\frac{{{a_3}}}{{{a_1}}} = 25$ થાય તો $\frac {{{a_9}}}{{{a_{  5}}}}$ ની કિમત મેળવો. 

A

$5^4$

B

$4(5^2)$

C

$5^3$

D

$2(5^2)$

(JEE MAIN-2019)

Solution

$\frac{{{a_3}}}{{{a_1}}} = \frac{{{a_1}{r^2}}}{{{a_1}}} = {r^2}$

$ \Rightarrow {r^2} = 25$

Now $\frac{{{a_9}}}{{{a_5}}} = \frac{{{a_1}{r^8}}}{{{a_1}{r^4}}} = {r^4} = {\left( {25} \right)^2} = {5^4}$

Standard 11
Mathematics

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