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Question

Using quadratic formula,

$x=\frac{(\cos 	heta \sin 	heta+1) \pm \sqrt{(\cos 	heta \sin 	heta+1)^{2}-4 \sin 	heta \cos 	heta}}{2 \sin 	heta}$

Vedclass · Accepted Answer

$\frac{1}{{1 - \cos \,	heta }} + \frac{1}{{1 + \sin \,	heta \,}}$

Vedclass · Answer

Using quadratic formula,

$x=\frac{(\cos 	heta \sin 	heta+1) \pm \sqrt{(\cos 	heta \sin 	heta+1)^{2}-4 \sin 	heta \cos 	heta}}{2 \sin 	heta}$

$=\frac{(\cos 	heta \sin 	heta+1)^{2} \pm(\cos 	heta \sin 	heta-1)}{2 \sin 	heta}$

$ = \cos \,	heta ,\,\cos ec\,	heta $

$\alpha  = \cos \,	heta ,\,\beta  = \cos ec\,	heta $

$	herefore \,\sum\limits_{n = 0}^\infty  {{\alpha ^n}}  + \frac{{{{( - 1)}^n}}}{{{\beta ^n}}}$

$ = \sum\limits_{n = 0}^\infty  {{{(\cos ec)}^n}}  + \sum\limits_{n = 0}^\infty  {{{( - \sin 	heta )}^n}} $

$=\frac{1}{1-\cos 	heta}+\frac{1}{1+\sin 	heta}$

$	herefore $ $(C)$ is the correct

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