3 and 4 .Determinants and Matrices
easy

$A=\left[\begin{array}{ll}2 & 4 \\ 3 & 2\end{array}\right], B=\left[\begin{array}{cc}1 & 3 \\ -2 & 5\end{array}\right], C=\left[\begin{array}{cc}-2 & 5 \\ 3 & 4\end{array}\right]$  હોય, તો $A-B$  મેળવો 

A

$\left[ {\begin{array}{*{20}{c}}   1&1 \\    5&{ - 3}  \end{array}} \right]$

B

$\left[ {\begin{array}{*{20}{c}}   1&1 \\    5&{ - 3}  \end{array}} \right]$

C

$\left[ {\begin{array}{*{20}{c}}   1&1 \\    5&{ - 3}  \end{array}} \right]$

D

$\left[ {\begin{array}{*{20}{c}}   1&1 \\    5&{ - 3}  \end{array}} \right]$

Solution

$A – B = \left[ {\begin{array}{*{20}{l}}
  2&4 \\ 
  3&2 
\end{array}} \right] – \left[ {\begin{array}{*{20}{c}}
  1&3 \\ 
  { – 2}&5 
\end{array}} \right]$

$ = \left[ {\begin{array}{*{20}{c}}
  {2 – 1}&{4 – 3} \\ 
  {3 – ( – 2)}&{2 – 5} 
\end{array}} \right]$

$ = \left[ {\begin{array}{*{20}{c}}
  1&1 \\ 
  5&{ – 3} 
\end{array}} \right]$

Standard 12
Mathematics

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