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मान लीजिए कि $A =\left[\begin{array}{ll}2 & 4 \\ 3 & 2\end{array}\right], B =\left[\begin{array}{cc}1 & 3 \\ -2 & 5\end{array}\right], C =\left[\begin{array}{cc}-2 & 5 \\ 3 & 4\end{array}\right],$ तो निम्नलिखित ज्ञात कीजिए:
$A-B$
$\left[ {\begin{array}{*{20}{c}}
1&1 \\
5&{ - 3}
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{c}}
1&1 \\
5&{ - 3}
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{c}}
1&1 \\
5&{ - 3}
\end{array}} \right]$
$\left[ {\begin{array}{*{20}{c}}
1&1 \\
5&{ - 3}
\end{array}} \right]$
Solution
$A – B = \left[ {\begin{array}{*{20}{l}}
2&4 \\
3&2
\end{array}} \right] – \left[ {\begin{array}{*{20}{c}}
1&3 \\
{ – 2}&5
\end{array}} \right]$
$ = \left[ {\begin{array}{*{20}{c}}
{2 – 1}&{4 – 3} \\
{3 – ( – 2)}&{2 – 5}
\end{array}} \right]$
$ = \left[ {\begin{array}{*{20}{c}}
1&1 \\
5&{ – 3}
\end{array}} \right]$