14.Probability
easy

मान लें $A$ और $B$ स्वतंत्र घटनाएँ हैं तथा $P ( A )=0.3$ और $P ( B )=0.4 .$ तब $P ( A \cup B )$ ज्ञात कीजिए।

A

$0.58$

B

$0.58$

C

$0.58$

D

$0.58$

Solution

It is known that, $P(A \cup B)=P(A)+P(B)-P(A \cap B)$

$\Rightarrow $ $P(A \cup B)=0.3+0.4-0.12=0.58$

Standard 11
Mathematics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.