Let $A=\{1,2,3, \ldots, 14\} .$ Define a relation $R$ from $A$ to $A$ by $R = \{ (x,y):3x - y = 0,$ where $x,y \in A\} .$ Write down its domain, codomain and range.
The relation $R$ from $A$ to $A$ is given as $R = \{ (x,y):3x - y = 0,{\rm{ }}$ where $x,y \in A\} $
ie., $R=\{(x, y): 3 x=y, $ where $ x, y \in A\}$
$\therefore R=\{(1,3),(2,6),(3,9),(4,12)\}$
The domain of $R$ is the set of all first elements of the ordered pairs in the relation.
$\therefore$ Domain of $R=\{1,2,3,4\}$
The whole set $A$ is he codomain of the relation $R$.
$\therefore$ Codomain of $R=A=\{1,2,3 \ldots .14\}$
The range of $R$ is the set of all second elements of the ordered pairs in the relation.
$\therefore$ Range of $R=\{3,6,9,12\}$
Let $R$ be a relation from $N$ to $N$ defined by $R =\left\{(a, b): a, b \in N \text { and } a=b^{2}\right\} .$ Are the following true?
$(a, a) \in R ,$ for all $a \in N$
Define a relation $R$ on the set $N$ of natural numbers by $R=\{(x, y): y=x+5$ $x $ is a natural number less than $4 ; x, y \in N \} .$ Depict this relationship using roster form. Write down the domain and the range.
Let $A=\{1,2\}$ and $B=\{3,4\} .$ Find the number of relations from $A$ to $B .$
$A=\{1,2,3,5\}$ and $B=\{4,6,9\} .$ Define a relation $R$ from $A$ to $B$ by $R = \{ (x,y):$ the difference between $ x $ and $ y $ is odd; ${\rm{; }}x \in A,y \in B\} $ Write $R$ in roster form.
Let $R$ be a relation from $N$ to $N$ defined by $R =\left\{(a, b): a, b \in N \text { and } a=b^{2}\right\} .$ Are the following true?
$(a, b) \in R ,(b, c) \in R$ implies $(a, c) \in R$