Let $R$ be a relation from $N$ to $N$ defined by $R =\left\{(a, b): a, b \in N \text { and } a=b^{2}\right\} .$ Are the following true?
$(a, b) \in R ,(b, c) \in R$ implies $(a, c) \in R$
Let $R$ be a relation from $N$ to $N$ defined by $R =\left\{(a, b): a, b \in N \text { and } a=b^{2}\right\} .$ Are the following true?
$(a, b) \in R ,(b, c) \in R$ implies $(a, c) \in R$
$R=\left\{(a, b): a, b \in N \text { and } a=b^{2}\right\}$
It can be seen that $(9,3) \in R,(16,4) \in R$ because $9,3,16,4 \in N$ and $9=3^{2}$ and $16=4^{2}$
Now, $9 \neq 4^{2}=16 ;$ therefore, $(9,4)$ $\notin N$
Therefore, the statement $''(a, b) \in R,(b, c) \in R$ implies $(a, c) \in R^{\prime \prime}$ is not true.
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