Let C be a circle passing through the points | vedclass

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Question

$AB =\sqrt{26}$

$r ^{2}= CM ^{2}+ AM ^{2}$

$=\left(2 	imes \sqrt{\frac{13}{2}}ight)^{2}+\left(\sqrt{\frac{13}{2}}ight)^{2}$

$r ^{2}=\fra

Vedclass · Accepted Answer

$\frac{65}{2}$

Vedclass · Answer

$AB =\sqrt{26}$

$r ^{2}= CM ^{2}+ AM ^{2}$

$=\left(2 	imes \sqrt{\frac{13}{2}}ight)^{2}+\left(\sqrt{\frac{13}{2}}ight)^{2}$

$r ^{2}=\frac{65}{2}$

Let $C$ be a circle passing through the points $A (2,-1)$ and $B (3,4)$. The line segment $AB$ is not a diameter of $C$. If $r$ is the radius of $C$ and its centre lies on the circle $(x-5)^{2}+(y-1)^{2}=\frac{13}{2}$, then $r^{2}$ is equal to

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