Let $A :\{1,2,3,4,5,6,7\}$. Define $B =\{ T \subseteq A$ : either $1 \notin T$ or $2 \in T \}$ and $C = \{ T \subseteq A : T$ the sum of all the elements of $T$ is a prime number $\}$. Then the number of elements in the set $B \cup C$ is $\dots\dots$
$107$
$106$
$105$
$108$
The shaded region in the given figure is
Let $A=\{2,4,6,8\}$ and $B=\{6,8,10,12\} .$ Find $A \cup B$
If $A, B$ and $C$ are non-empty sets, then $(A -B) \cup (B -A)$ equals
Is it true that for any sets $\mathrm{A}$ and $\mathrm{B}, P(A) \cup P(B)=P(A \cup B) ?$ Justify your answer.
$A$ and $B$ are two subsets of set $S$ = $\{1,2,3,4\}$ such that $A\ \cup \ B$ = $S$ , then number of ordered pair of $(A, B)$ is