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1.Relation and Function
easy
Let $P = \{ (x,\,y)|{x^2} + {y^2} = 1,\,x,\,y \in R\} $. Then $P$ is
A
Reflexive
B
Symmetric
C
Transitive
D
Anti-symmetric
Solution
(b) Obviously, the relation is not reflexive and transitive but it is symmetric, because ${x^2} + {y^2} = 1 \Rightarrow {y^2} + {x^2} = 1$.
Standard 12
Mathematics