Let P = { (x,,y)|{x^2} + {y^2} = 1,,x,,y ∈ R} . Then P is

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1.Relation and Function

easy

Let $P = \{ (x,\,y)|{x^2} + {y^2} = 1,\,x,\,y \in R\} $. Then $P$ is

A

Reflexive

B

Symmetric

C

Transitive

D

Anti-symmetric

Solution

(b) Obviously, the relation is not reflexive and transitive but it is symmetric, because ${x^2} + {y^2} = 1 \Rightarrow {y^2} + {x^2} = 1$.

Standard 12

Mathematics

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