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1.Relation and Function
easy
જો$P = \{ (x,\,y)|{x^2} + {y^2} = 1,\,x,\,y \in R\} $.તો $P$ એ .. . . થાય.
A
સ્વવાચક
B
સંમિત
C
પરંપરિત
D
વિસંમિત
Solution
(b) Obviously, the relation is not reflexive and transitive but it is symmetric, because ${x^2} + {y^2} = 1 \Rightarrow {y^2} + {x^2} = 1$.
Standard 12
Mathematics