1.Relation and Function
easy

જો$P = \{ (x,\,y)|{x^2} + {y^2} = 1,\,x,\,y \in R\} $.તો  $P$ એ  .. .  . થાય.  

A

સ્વવાચક

B

સંમિત 

C

પરંપરિત

D

વિસંમિત

Solution

(b) Obviously, the relation is not reflexive and transitive but it is symmetric, because ${x^2} + {y^2} = 1 \Rightarrow {y^2} + {x^2} = 1$.

Standard 12
Mathematics

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